Answer: [tex](1006.68\ cm/sec,\ 1143.32\ cm/sec)[/tex]
Step-by-step explanation:
As per given we have,
n=60
[tex]\overline{x}=1075\ cm/sec\\\\ \sigma=270\ cm/sec[/tex]
Critical value for 95% confidence : [tex]z_{\alpha/2}=1.96[/tex]
Confidence interval :
[tex]\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\=1075+(1.96)\dfrac{270}{\sqrt{60}}\\\\\approx1075\pm68.3194\\\\=(1075-68.32,\ 1075+68.32)\\\\= (1006.68,\ 1143.32)[/tex]
Hence, a 95% confidence interval for the population mean wind speed at this site. = [tex](1006.68\ cm/sec,\ 1143.32\ cm/sec)[/tex]