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A woman stands on a bathroom scale in a motionless elevator. When the elevator begins to move, the scale briefly reads only 0.79 of her regular weight.
(a) Calculate the magnitude of the acceleration of the elevator.
(b) Find the direction of the acceleration.

Respuesta :

Answer:

Part a)

[tex]a = 2.06 m/s^2[/tex]

Part b)

Lift is moving downwards as it is coming with negative sign

Explanation:

As we know that the reading of the scale is equal to the normal force on the woman

So we will have

[tex]F_n - mg = ma[/tex]

here we know that

[tex]F_n = 0.79 mg[/tex]

so we will have

[tex]0.79 mg - mg = ma[/tex]

[tex]a = -2.06 m/s^2[/tex]

Part a)

magnitude of the acceleration of the lift is given as

[tex]a = 2.06 m/s^2[/tex]

Part b)

Lift is moving downwards as it is coming with negative sign

a) The magnitude of the acceleration of the elevator is  [tex]a=2.06m/s^2[/tex]

b) The direction of the acceleration is in downward direction having negative sign.

Normal Force:

It is the force that surfaces exert to prevent solid objects from passing through each other.

As we know that the reading of the scale is equal to the normal force on the woman

[tex]F_n=mg=ma[/tex]

Part a)

Given:

[tex]F_n=0.79mg[/tex]

Adding this value in above equation:

[tex]F_n=mg=ma\\\\0.79mg=mg=ma\\\\a=2.06m/s^2[/tex]

Thus, the magnitude of acceleration is, [tex]a=2.06m/s^2[/tex]

Part b)

Lift is moving downwards as it is coming with negative sign.

Find more information about Normal Force here:

brainly.com/question/10941832

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