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Consider the lattice energies of the following Group 2A compounds: BeH2, 3205 kJ/mol; MgH2, 2791 kJ/mol; CaH2, 2410 kJ/mol; SrH2, 2250 kJ/mol; BaH2, 2121 kJ/mol. Part A What is the oxidation number of H in these compounds?

Respuesta :

Answer:

(-1) is the oxidation number of H in these compounds.

Explanation:

Oxidation state is defined as the number that is given to an atom when it looses or gains electron. It is always written as a superscript.

  • When an atom looses electron, it will attain a positive oxidation state.
  • When an atom gains electron, it will attain a negative oxidation state.

Elements of group-2 have fixed oxidation state that +2.

Oxidation of Hydrogen atom in all [tex]BeH_2, MgH_2,CaH_2,SrH_2\& BaH_2[/tex] :

Oxidation state of each metal in the given compounds = +2

Let the oxidation state of hydrogen atom be = x

Since, these given compounds are neutral that is overall charge on the compound is 0.

[tex]1\times (+2)+2x=0[/tex]

[tex]x=\frac{-2}{2}=-1[/tex]

(-1) is the oxidation number of H in these compounds.

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