Answer:
See answer
Explanation:
The area of the circular loop is given by:
[tex]A = \pi r^2[/tex]
The magnetic flux is given by:
[tex]\phi = \int \vec{B} \cdot d\vec{A}[/tex]
[tex]d\vec{A}[/tex] is parallel to [tex]\vec{B}[/tex] and [tex]\vec{B}[/tex] is constant in magnitude and direction therefore:
[tex]\phi = \int \vec{B} \cdot d\vec{A}= \int BdAcos(0)= B\int dA= B*(\pi r^2)= \pi Br^2[/tex]
Part A)
initially the flux is [tex]\phi =\pi B r^2[/tex]
after the interval [tex]\Delta t= 2.4 [m/s][/tex]
the flux is
[tex]\phi = 0[/tex]
now, the EMF is defined as:
[tex]\epsilon =- \frac{d \phi}{dt}[/tex],
if we consider [tex]\Delta t= 2.4 [m/s][/tex] very small then we can re-write it as:
[tex]\epsilon =- \frac{\Delta \phi}{\Delta t}[/tex]
[tex]\Delta \phi = 0 - \pi B r^2=-\pi (1.7) (0.15)^2=-0.12[/tex]
then:
[tex]\epsilon =- \frac{-0.12}{0.0024} = 50 [V][/tex]
Part B)
When looked down from above, the current flows counter clockwise, according to the right hand rule, if you place your thumb upwards (the direction of the magnetic field) and close your fingers, then the current will flow in the direction of your fingers.
