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Early investigators (including Thomas Young) measured the thickness of wool fibers using diffraction. One early instrument used a collimated beam of 560 nm light to produce a diffraction pattern on a screen placed 30 cm from a single wool fiber.
part a: If the fiber's diameter was 18 Ī¼m, what was the width of the central maximum on the screen?

Respuesta :

Manetho

Answer:

[tex]w= 1.867\times10^{-2}[/tex]

Explanation:

Given:

fibers diameter d= 18 Ī¼m

distance of the screen D= 30 cm

wavelength Ī»= 560 nm

we know that fringe width

[tex]w=\frac{2\lambda D}{d}[/tex]

putting values we get

[tex]w=\frac{2\times560\times10^{-9}\times0.3}{18\times10^{-6}[/tex]

[tex]w= 1.867\times10^{-2}[/tex]

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