Answer:
It requires 1.9 seconds to reach maximum height.
Explanation:
As per given question,
Initial velocity (U) =19 m/s
Final velocity (V) = 0 m/s
[tex]\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}[/tex]
Maximum height = S
Time taken is "t"
Calculating time taken to reach maximum height:
We know that time taken to reach the maximum height is calculated by using the formula V = U + at
Substitute the given values in the above equation.
Final velocity is “0” as there is no velocity at the maximum height.
[tex]0=19+10 \times t[/tex]
[tex]-19=10 \times t[/tex]
[tex]\frac{-19}{10}=t[/tex]
t = 1.9 seconds.
The time taken to reach maximum height is 1.9 seconds.
Calculating maximum height:
[tex]\text { Consider the equation } V^{2}-U^{2}=2 a S[/tex]
Solving the equation we will get the value of S
[tex]0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }[/tex]
-361 = -20S
Negative sign cancel both the sides.
[tex]\mathrm{S}=\frac{361}{20}[/tex]
S = 18.05 m
Maximum height is 18.05 m .
