Answer:
0.00411
Step-by-step explanation:
Given that a snap shot in USA Today indicates that 51% of Americans say the average person is not very considerate of others when talking on a cellphone.
Sample size n = 100
Sample proportion p is Normal with mean = 0.51 and variance = [tex]\frac{pq}{n} \\=\frac{0.51(0.49)}{100} \\=0.002419\\[/tex]
std dev = 0.049183
the approximate probability that 64 or more Americans would indicate that the average person is not very considerate of others when talking on a cellphone.
=[tex]P(p\geq 0.64)=\\P(Z\geq \frac{0.64-0.51}{0.049183} )\\\\=P(Z\geq 0.643)\\=0.00411[/tex]
