Respuesta :
Answer:
C
Explanation:
To solve this question, we will need to develop an expression that relates the diameter 'd', at temperature T equals the original diameter d₀ (at 0 degrees) plus the change in diameter from the temperature increase ( ΔT = T):
d = d₀ + d₀αT
for the sphere, we were given
D₀ = 4.000 cm
α = 1.1 x 10⁻⁵/degrees celsius
we have D = 4 + (4x(1.1 x 10⁻⁵)T = 4 + (4.4x10⁻⁵)T EQN 1
Similarly for the Aluminium ring we have
we were given
d₀ = 3.994 cm
α = 2.4 x 10⁻⁵/degrees celsius
we have d = 3.994 + (3.994x(2.4 x 10⁻⁵)T = 3.994 + (9.58x10⁻⁵)T EQN 2
Since @ the temperature T at which the sphere fall through the ring, d=D
Eqn 1 = Eqn 2
4 + (4.4x10⁻⁵)T =3.994 + (9.58x10⁻⁵)T, collect like terms
0.006=5.18x10⁻⁵T
T=115.7K
Temperature directs to the hotness or coldness of a body. it is the method of finding the kinetic energy of particles. At the temperature of 115°c will the sphere fall through the ring.
What is temperature?
Temperature directs to the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles more the temperature.
Temperature is essential in all areas of Science right from Physics to Geology and also it is important in most parts of our everyday life.
We have to form an equation that is used to find the temperature.
d = d₀ + d₀αT
D₀ is the initial diameter of 4.000 cm
α is the cofficeient= 1.1 x 10⁻⁵/degrees celsius
[tex]\rm D = 4 + (4\times(1.1 \times10^{-5})T[/tex]
[tex]\rm D= 4 + (4.4\times10^{-5})T[/tex]
The same formula applied to the aluminum ring
d₀ is the initial diameter for aluminum ring =3.994 cm
α is the coefficient = 2.4 x 10⁻⁵/degrees celsius
[tex]\rm d = 3.994 + (3.994\times(2.4 \times 10^{-5})\\\\\rm d = 3.994 + (9.58\times10^{-5})T[/tex]
According to conditions the temperature T at which the sphere fall through the ring, d=D
[tex]4 + (4.4\times10^{-5})T= 3.994 + (9.58\times10^{-5})T[/tex]
T=115.7K
Hence at the temperature of 115°c will the sphere fall through the ring.
To learn more about the temperature refer to the link;
https://brainly.com/question/7510619
