Answer:
e = 10 V
Explanation:
given,
number of the coaxial loops = 10
Cross sectional area = 0.5 m²
magnitude of magnetic field =
B = 3 T + (2 T/s)*t.
B = ( 3+ 2 t ) T
induced potential difference = ?
At time = 2 s
we know,
induced emf
[tex]e = - N\dfrac{d\phi}{dt}[/tex]
∅ = B . A
[tex]e = - N\dfrac{d(BA)}{dt}[/tex]
[tex]e = - NA\dfrac{dB}{dt}[/tex]
[tex]e = - 10 \times 0.5 \times \dfrac{d}{dt}(3 + 2 t)[/tex]
[tex]e = - 10 \times 0.5 \times 2[/tex]
e = -10 V
magnitude of induced emf
|e| = |-10 V|
e = 10 V
the induced potential difference in the loop = e = 10 V
