Answer:
The probability that she selects none of those containing errors is 0.68
Explanation:
We are given that 7 out of 59 tax returns contain errors and an IRS auditor selects 3 tax returns from 59, we have to find the probability of selecting error free returns.
The probability is given by = [tex]\frac{\text {selection of error free tax returns}}{\text {selection of } 3 \text { random tox returns}}[/tex]
=[tex]\frac{52 C 3}{59 C 3}[/tex]
=[tex]\frac{52 !}{3 ! 49 !} \div \frac{59 !}{3 ! 56 !}[/tex]
=0.68
Which is the required probability.
