Answer:
0.9655
Step-by-step explanation:
Given that a new computer virus attacks a folder consisting of 200 files
Probability for each file gets damaged = p = probability for success in each trial =[tex]0.2[/tex]
Each file is independent of the other.
Hence X no of files damaged is binomial with n =200 and p = 0.20
Here n denotes the number of files and p probability for success in each trial
We have [tex]q=1-0.2 =0.8[/tex]
Required probability [tex]=P(X\leq 50)\\=\Sigma _0^{50} 50Cr (0.2)^r (0.8)^{200-r}[/tex]
=0.9655
