Respuesta :
Answer:
0.0222 mole of NaOH is needed to react with NH4F
Explanation:
NH4F + NaOH --> NaF + NH3 + H2O
Data given
Mass of NH4F =0.821g, Concentration of NaOH= 1M, volume of NaoH =25ml
But mole = (CV)/1000
given mole of NaoH = (1 * 25)/1000 = 0.025moles of NaOH used
Molar mass of NH4F = 37g/mol
mole of NH4F used 0.821 / 37 = 0.0222 mole NH4F
Determine the excess and limiting reactant,
NaOH is in excess
0.025 - 0.0222 = 0.0028 mole NaOH excess
0.0222 mole of NaOH is required to react with NH4F
The number of moles of NaOH that are needed to react with the NH₄F is 0.0222 mole
From the question,
We are to determine the number of moles of NaOH that are needed to react with the NH₄F
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
NH₄F + NaOH → NH₃ + NaF + H₂O
This means,
1 mole of NH₄F is needed to completely react with 1 mole of NaOH
Now, we will determine the number of moles of NH₄F present in the reaction
From the given information
Mass of NH₄F = 0.821g
Using the formula
[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]
Molar mass of NH₄F = 37.04 g/mol
∴ Number of moles of NH₄F present = [tex]\frac{0.821}{37.04}[/tex]
Number of moles of NH₄F present = 0.022165 mole
Now,
From the balanced chemical equation
1 mole of NH₄F is needed to completely react with 1 mole of NaOH
Then,
0.022165 mole of NH₄F would completely react with 0.022165 mole of NaOH
∴ The number of moles of NaOH needed = 0.022165 mole
The number of moles of NaOH needed ≅ 0.0222 mole
Hence, the number of moles of NaOH that are needed to react with the NH₄F is 0.0222 mole
Learn more here: https://brainly.com/question/24817060
Here is the complete question:
A 0.821 gram sample of pure NH₄F was treated with 25.0mL of 1.00 M NaOH and heated to drive off the NH₃. How many mols of NaOH are needed to react with the NH4F?
