The equation is y = Three-halvesx + 1
Step-by-step explanation:
That line should be perpendicular to the given line : y-4 = -2/3 (x-6) and
It passes through (-2,-2)
Write the equation in slope-intercept form as;
y-4= -2/3 (x-6)
y-4=-2/3x + 4
y= -2/3x + 8
The slope m₁, of the equation is -2/3
For perpendicular lines, m₁*m₂= -1
So,finding m₂ where m₁ = -2/3
-2/3 * m₂ = -1
m₂ = -1 * - 3/2 = 3/2
The equation of the line passing through point (-2,-2) with m₂=3/2 will be;
y--2/x--2 = 3/2
y+2/x+2=3/2
2(y+2)=3(x+2)
2y+4=3x+6
2y=3x+6-4
2y=3x+2
y=3/2x +1 ⇒⇒Three-halves *x+1
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Equation of perpendicular lines : https://brainly.com/question/11482954
Keyword : equation, slope-intercept form, perpendicular
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