The acceleration of the block is [tex]-0.98 m/s^2[/tex]
Explanation:
The expression for the force of friction acting on the block is (assuming the surface is horizontal and flat):
[tex]F_f = -\mu mg[/tex]
where
[tex]\mu[/tex] is the coefficient of friction
m is the mass of the block
g is the acceleration of gravity
and where the negative sign means the direction of the force is opposite to that of the motion of the block
If this is the only force acting on the object, then this is also the resultant force, so we can rewrite Newton's second law as:
[tex]F=ma\\-\mu mg = ma[/tex]
where
a is the acceleration of the block
Re-arranging the equation,
[tex]a=-\mu g[/tex]
And so this is the expression for the acceleration of the block acted upon the force of friction.
In this problem, we have:
[tex]\mu=0.1[/tex]
[tex]g=9.8 m/s^2[/tex]
Solving,
[tex]a=-(0.1)(9.8)=-0.98 m/s^2[/tex]
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