Answer:
229 [tex]\textbf{m}^{\textbf{2}}[/tex]
Step-by-step explanation:
The Entire shaded diagram can be divided into three regions or parts. Two of these parts are semicircles with radius [tex]5\text{ }m[/tex], the other is a rectangle of length [tex]15\text{ }m[/tex] and it's breadth is equal to the diameter of the semicircle, which is [tex]10\text{ }m[/tex].
Total Area = [tex]2\times(\text{Area of semicircle})+(\text{Area of rectangle})[/tex]
= [tex]2(\frac{\pi r^{2}}{2})+(l\times b)=\pi r^{2}+l\times b[/tex]
= [tex]\pi (5)^{2}+15\times 10=25\pi+150=228.54\text{ }m^{2}[/tex]
∴ Total Area of diagram = [tex]228.54 \text{ }m^{2}[/tex] ≈ [tex]229 \text{ }m^{2}[/tex]
