contestada

The two solids below are similar, and the ratio between the lengths of their edges 4:7 what is the ratio of their surface areas

Respuesta :

Answer: 16: 49

Step-by-step explanation:

If two shapes are similar , then the following condition holds

(i) the ratio of their sides are equal

(ii) If [tex]l_{1}[/tex] is the length of the first one and [tex]l_{2}[/tex] is the length of the second one then:

[tex]\frac{A_{1} }{A_{2} }[/tex] = [tex]\frac{(L_{1} )^{2} }{L_{2}) ^{2} }[/tex]

Where A stands for the area

(iii)  [tex]\frac{V_{1} }{V_{2} }[/tex] = [tex]\frac{(L_{1} )^{3} }{L_{2}) ^{3} }[/tex]

Following theses conditions , the ratio of the lengths of their edges is given to be 4 : 7 , then the ratio of their surface area implies:

[tex]\frac{A_{1} }{A_{2} }[/tex] = [tex]\frac{4^{2} }{7^{2} }[/tex]

[tex]\frac{A_{1} }{A_{2} }[/tex] = 16/49

Therefore the ratio of their surface area is 16: 49

Answer:

16:49

Step-by-step explanation:

A P E X