The work done is [tex]2.35\cdot 10^5 J[/tex]
Explanation:
The work done by a force on an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we have
F = 1080 N is the force applied on the car
d = 218 m is the displacement of the car
And assuming the force is applied parallel to the motion of the car, [tex]\theta=0^{\circ}[/tex], and so the work done is
[tex]W=(1080)(218)(cos 0^{\circ})=2.35\cdot 10^5 J[/tex]
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
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