Answer:
L = 1.023 H
Explanation:
given,
radius of the cylindrical solenoid = r = 0.6 m
Number of turns = N = 600
Length = l = 0.5 m
Current in the cylindrical solenoid = 15 A
Inductance in the coil = ?
using formula
[tex]L = \dfrac{\mu_0\ N^2\ A}{l}[/tex]
[tex]L = \dfrac{4 \pi \times 10^{-7}\times 600^2\times \pi r^2}{0.5}[/tex]
[tex]L = \dfrac{4 \pi \times 10^{-7}\times 600^2\times \pi 0.6^2}{0.5}[/tex]
[tex]L = \dfrac{4 \pi \times 10^{-7}\times 600^2\times \pi 0.6^2}{0.5}[/tex]
L = 1.023 H
the inductance L of the coil is = 1.023 H
