Respuesta :
Answer:
[tex]\Delta KE=3.71\times 10^{-15}\ J[/tex]
Explanation:
It is given that,
Potential difference, [tex]PE=2.32\times 10^4\ V[/tex]
Using the conservation of energy as the potential energy lost by an electron gets converted to the kinetic energy gained by it. Its relation is given by :
[tex]\Delta KE=\Delta PE[/tex]
Since, [tex]\Delta PE=q\Delta V[/tex]
[tex]\Delta KE=q\Delta V[/tex]
[tex]\Delta KE=1.6\times 10^{-19}\times 2.32\times 10^4\ V[/tex]
[tex]\Delta KE=3.71\times 10^{-15}\ J[/tex]
So, the kinetic energy gained by the electron is [tex]3.71\times 10^{-15}\ J[/tex]
Answer:
3.712 x 10^-15 J
Explanation:
Potential difference, V = 2.32 x 10^4 V
Charge of electron, e = 1.6 x 10^-19 J
The kinetic energy of the electron is
K = e x V
K = 1.6 x 10^-19 x 2.32 x 10^4 J
K = 3.712 x 10^-15 J
Thus, the kinetic energy of the electron is 3.712 x 10^-15 J.
