The solubility of Cr(NO3)3⋅9H2O in water is 208 g per 100 g of water at 15 ∘C. A solution of Cr(NO3)3⋅9H2O in water at 35 ∘C is formed by dissolving 310 g in 100 g water. When this solution is slowly cooled to 15 ∘C, no precipitate forms. At equilibrium, what mass of crystals do you expect to form?

When the Cr(NO₃)₃⋅9H₂O is dissolved in water at 15°C, the maximum mass that water will dissolve in the equilibrium is 208 g per 100g of water. When you heat the water, this mass will increases.

In this problem, at 35°C the water dissolves 310g in 100g of water, as in the equilibrium at 15°C the maximum mass is 208g, the mass of crystals that will form is:

310g - 208g = 102g of crystals

-Crystals are the Cr(NO₃)₃⋅9H₂O that is not dissolved-.

I hope it helps!

tutorareej tutorareej · Answer 2 · 2021-11-30T08:23:29+01:00

The expected mass of the crystals at equilibrium has been 102 grams.

Solubility can be defined as the maximum amount of solute that can be dissolved in a solvent at a specific temperature.

The solubility of chromium nitrate has been 208 g per 100 grams at 25 degrees celsius. On heating, the solubility of the solution increases while on cooling the solubility decreases and solute precipitates out.

At 15[tex]\rm ^\circ C[/tex], the solubility of the solution decreases, thus the solution has been supersaturated solution.

The metal spatula has the crystal of Chromium nitrate, as they have been precipitated out from the solution due to a decrease in solubility.

The mass of crystal that has been expected at equilibrium has been the mass that remained undissolved.

The dissolved mass = 208 grams

The total mass = 310 grams

Undissolved mass = 310 - 208

Undissolved mass = 102 grams.

The expected mass of the crystals at equilibrium has been 102 grams.

For more information about solubility, refer to the link:

https://brainly.com/question/11228968