Answer: The mass of potassium superoxide required is 142.2 grams
Explanation:
The chemical equation for the reaction of potassium superoxide with water follows:
[tex]2KO_2+H_2O\rightarrow KOH+KHO_2+O_2;\Delta H=2405J[/tex]
Number of moles of potassium superoxide reacted = 2 moles for given amount of heat released
To calculate the mass for given number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of potassium superoxide = 71.1 g/mol
Moles of potassium superoxide = 2 moles
Putting values in above equation, we get:
[tex]2mol=\frac{\text{Mass of potassium superoxide}}{71.1g/mol}\\\\\text{Mass of potassium superoxide}=(2mol\times 71.1g/mol)=142.2g[/tex]
Hence, the mass of potassium superoxide required is 142.2 grams
