The specific heat of the metal is [tex]0.037 J(g^{\circ}C)[/tex]
Explanation:
When a sample of a material absorbs energy, its temperature increases according to the equation
[tex]Q=m C_s \Delta T[/tex]
where
Q is the amount of energy supplied to the sample
m is the mass of the sample
Cs is its specific heat capacity
[tex]\Delta T[/tex] is the increase in temperature
In this problem,
m = 50.0 g
Q = 220.0 J
[tex]\Delta T =120.0^{\circ}C[/tex]
Solving for C_s, we find the specific heat capacity:
[tex]C_s = \frac{Q}{m\Delta T}=\frac{220.0}{(50.0)(120.0)}=0.037 J(g^{\circ}C)[/tex]
Learn more about specific heat capacity:
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