Answer:
Maximum speed of the coin, v = 0.607 m/s
Explanation:
It is given that,
A coin rests on a record 0.13 m from its center i.e. the radius of the circular path, r = 0.13 m
The coefficient of static friction between the coin and the record is, [tex]\mu=0.29[/tex]
The centripetal force acting on the coin is balanced by the frictional force. Its mathematical relation is given by :
[tex]\dfrac{mv^2}{r}=\mu mg[/tex]
[tex]v=\sqrt{\mu gr}[/tex]
[tex]v=\sqrt{0.29\times 9.8\times 0.13}[/tex]
v = 0.607 m/s
So, the maximum coin speed at which it does not slip is 0.607 m/s. Hence, this is the required solution.