Answer: Zinc will react with lead (II) nitrate solution.
Explanation:
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.
General equation for single displacement reaction follows:
[tex]A+BC\rightarrow AC+B[/tex]
When zinc is reacted with calcium nitrate, the reaction does not take place as zinc is less reactive than calcium. Zinc lies below in the series than calcium.
[tex]Zn+Ca(NO_3)_2\rightarrow \text{No reaction}[/tex]
But, when zinc is reacted with lead (II) nitrate, the reaction do take place as zinc is more reactive than lead. Zinc lies above in the series than lead.
The chemical equation for the reaction of zinc and lead (II) nitrate follows:
[tex]Zn+Pb(NO_3)_2\rightarrow Zn(NO_3)_2+Pb[/tex]
Hence, zinc will react with lead (II) nitrate solution.
Zinc will react with 1.60 M lead(II) nitrate solution because zinc is higher than lead in the electrochemical series.
The electrochemical series shows the order of reactivity of elements. More reactive elements are found at the top of the series while less reactive elements are found at the bottom of the series.
Calcium is higher than zinc in the electrochemical series and zinc is higher than lead in the electrochemical series . Note that an element can displace a metal that is lower in the series than itself from its aqueous solution.
As such, we expect that zinc should react with lead and displace it from aqueous solution according to the reaction equation; Zn(s) + Pb(NO3)2 -----> Zn(NO3)2(aq) + Pb(s).
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