Respuesta :
Answer : The Lewis-dot structure for the following molecules are shown below.
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
Now we have to determine the Lewis-dot structure for the following molecules.
(a) The given molecule is, [tex]ICl[/tex]
As we know that iodine and chlorine have '7' valence electrons.
Therefore, the total number of valence electrons in [tex]ICl[/tex] = 7 + 7 = 14
According to Lewis-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.
(b) The given molecule is, [tex]PH_3[/tex]
As we know that phosphorous has '5' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in [tex]PH_3[/tex] = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
(c) The given molecule is, [tex]P_4[/tex]
As we know that phosphorous has '5' valence electrons.
Therefore, the total number of valence electrons in [tex]P_4[/tex] = 4(5) = 20
According to Lewis-dot structure, there are 6 number of bonding electrons and 14 number of non-bonding electrons.
(d) The given molecule is, [tex]H_2S[/tex]
As we know that sulfur has '6' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in [tex]H_2S[/tex] = 6 + 2(1) = 8
According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.
(e) The given molecule is, [tex]N_2H_4[/tex]
As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in [tex]N_2H_4[/tex] = 2(5) + 4(1) = 14
According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.
(f) The given molecule is, [tex]HClO_3[/tex]
As we know that chlorine has '7' valence electrons, oxygen has '6' valence electrons and hydrogen has '1' valence electrons.
Therefore, the total number of valence electrons in [tex]HClO_3[/tex] = 1 + 7 + 3(6) = 26
According to Lewis-dot structure, there are 12 number of bonding electrons and 14 number of non-bonding electrons.
(g) The given molecule is, [tex]COBr_2[/tex]
As we know that bromine has '7' valence electrons, oxygen has '6' valence electrons and carbon has '4' valence electrons.
Therefore, the total number of valence electrons in [tex]COBr_2[/tex] = 4 + 6 + 2(7) = 24
According to Lewis-dot structure, there are 8 number of bonding electrons and 16 number of non-bonding electrons.
