Respuesta :
Answer:53.63[tex]ms^{-2}[/tex]
Explanation:
The equations of motion used in this question is [tex]v=u+at[/tex]
When a object is projected horizontally from a sufficiently height,the x-component of acceleration remains zero because there is no force that drags the object in x direction.
But,due to gravity,the object accelerates downward at a rate of [tex]9.8ms^{-2}[/tex].
In X-Direction,
Given that initial velocity=[tex]u_{x}[/tex]=[tex]33.8ms^{-1}[/tex]
Using [tex]v=u+at[/tex],
[tex]v_{x}=33.8+(0)4.25=33.8ms^{-1}[/tex]
In Y-Direction,
Given that initial velocity=[tex]u_{x}[/tex]=[tex]0ms^{-1}[/tex]
Using [tex]v=u+at[/tex],
[tex]v_{y}=0+(9.8)4.25=41.65ms^{-1}[/tex]
[tex]v=\sqrt{v_{x}^{2}+v_{y}^{2}}[/tex]
[tex]v=\sqrt{1142.44+1734.72}=\sqrt{2877.163}=53.63ms^{-1}[/tex]
Answer:53.6722
Explanation:If anyone is taking Acellus, trust me, this is the answer.
