Answer:
Emil's backpack weighs [tex]7\frac{5}{8}[/tex] pounds
Step-by-step explanation:
Given:
Weight of Emil's backpack=[tex]6\frac{3}{8}[/tex]
Weight of book 1 =[tex]\frac{3}{4}[/tex]
Weight of book 2 =[tex]\frac{1}{2}[/tex]
To Find:
The weight of Emil's backpack after books are removed=?
Solution:
weight of Emil's backpack after books are removed= Weight of backpack -Weight of book 1- Weight of book 2
Substituting the values,
weight of Emil's backpack after books are removed=[tex]6\frac{3}{8}-\frac{3}{4}-\frac{1}{2}[/tex]
=>[tex]\frac{51}{8}-\frac{3}{4}-\frac{1}{2}[/tex] (converting mixed fraction into normal fraction}
Taking LCM for the denominators
8= 2 x 2 x 2
4= 2 x 2
2= 2 x 1
Least Common Multiple(8,4,2) = 2 x 2 x 2
Least Common Multiple(8,4,2) = 8
so
=>[tex]\frac{51}{8}+\frac{6}{8}+\frac{4}{8}[/tex]
=>[tex]\frac{51+6+4}{8}[/tex]
=>[tex]\frac{61}{8}[/tex]
=>[tex]7\frac{5}{8}[/tex]
