Select all that are true for a titration of 0.20 M KHP with 0.20 M HCl as the titrant as compared to your titration with 0.20 M NaOH as the titrant in the lab. (Select all that apply.)
1. The equivalence volume would be the same.
2. The pH at the equivalence point would be the same.
3. Phenolphthalein would be an appropriate indicator.
4. The initial pH would be the same.
5. The pH at the midpoint would be the same

The pH will not be the same because with HCl you are adding acid decreasing pH and for the second reaction NaOH is a base that increase pH. For the same reason, in the midpoint pH wouldn't be the same.

Phenolphtalein wouldn't be an appropriate indicator because the useful pH range is between 6,0 and 7,6 and the equivalence points are in 7,2 and 10,6.

4. The initial pH would be the same. That's true because in the two titrations you will have just 0,20M KHP in solution.

I hope it helps!

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-01T12:05:19+02:00

Given the Chemical Reaction we decipher that, The equivalence volume would be the same. and The initial pH would be the same.

Option A and D is correct

What is true about a a titration of 0.20 M KHP with 0.20 M HCl ?

Question Parameter(s):

a titration of 0.20 M KHP with 0.20 M HCl as the titrant

your titration with 0.20 M NaOH as the titrant in the la

Generally, the equation for the Chemical Reaction is mathematically given as

KHP + HCl ----> H₂P + KCl

KHP + NaOH ----> P^{2-} + H2O + K+ + Na+

In conclusion, Since molar concentration of HCl is same with the molar concentration of NaOH,The equivalence volume would be the same, and The initial pH would be the same