Answer:
The kinetic energy of box b is 2.44 J.
Explanation:
Given that,
Mass of box a =3.00 kg
Mass of box b=1.00 kg
Distance = 1.00 m
We need to calculate the acceleration of the system
Using formula of acceleration
[tex]a=\dfrac{m_{2}\times g}{m_{1}+m_{2}}[/tex]
put the value into the formula
[tex]a=\dfrac{1.00\times9.8}{1.00+3.00}[/tex]
[tex]a=2.45\ m/s^2[/tex]
We need to calculate the velocity
Using equation of motion
[tex]v^2=u^2+2as[/tex]
Put the value into the formula
[tex]v^2=0+2\times2.45\times1.00[/tex]
[tex]v=\sqrt{2\times2.45\times1.00}[/tex]
[tex]v=2.21\ m/s[/tex]
We need to calculate the kinetic energy of box b
Using formula of energy
[tex]K.E=\dfrac{1}{2}mv^2[/tex]
Put the value into the formula
[tex]K.E=\dfrac{1}{2}\times1.00\times(2.21)^2[/tex]
[tex]K.E=2.44\ J[/tex]
Hence, The kinetic energy of box b is 2.44 J.
The kinetic energy of box just before it reaches the floor is 10N.
Energy is the ability to do work. Types of energy are potential, kinetic and so on.
Potential energy is the energy possessed by a body due to its position relative to another object while kinetic energy is the energy due to motion.
The potential energy of the box = mass * acceleration due to gravity * height * height = 1 kg * 10 m/s² * 1 m = 10 N
Since energy is transformed, hence:
Kinetic energy of box b just before it reaches the floor = Potential energy = 10N
The kinetic energy of box just before it reaches the floor is 10N.
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