Answer:
4.67 m/s
Step-by-step explanation:
The equation of continuity for an incompressible fluid is A1v1 = A2v2 where A represents area and v is velocity of the fluid.
If we let the values with subscript 1 be those inside the hose and 2 be those at the nozzle then the question can be solved this way
[tex]A_{1} v_{1} = A_{2} v_{2} \\\\(\pi *0.01125^{2} )*v_{1} = (\pi *0.00065^{2} )*14\\\\v_{1} = 4.67 m/s[/tex]
