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2. A man heats a balloon in the oven. If the balloon initially
has a volume of 0.9 liters and a temperature of 20°C,
what will the volume of the balloon be after he heats it to
a temperature of 230°C?

Respuesta :

Neetoo

Answer:

V₂ = 1.55 L

Explanation:

Given data:

Initial volume = 0.9 L

Initial temperature = 20°C

Final volume = ?

Final temperature = 230°C

Solution:

20°C  = 20+273 = 293 k

230°C  = 230+273 = 503 K

According to Charles law,

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ =  0.9 L . 503 K/ 293 k

V₂ =  452.7 L.K  /293 k

V₂ = 1.55 L

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