Answer:
Speed=1.633 m/s
Force= 20 N
Explanation:
Ideally, [tex]v^{2}=\frac {ks^{2}}{m}[/tex] hence [tex]v=s\sqrt {\frac {k}{m}}[/tex] where v is the speed of collar, m is the mass of collar, k is spring constant and s is the displacement.
In this case, s=100-0=100mm=0.1m since 1 m is equivalent to 1000mm
k is given as 200 N/m and mass is 0.75 Kg
Substituting the given values
[tex]v=0.1 m\sqrt \frac {200 N/m}{0.75 Kg}=1.632993162 m/s\approx 1.633 m/s[/tex]
Therefore, the speed is 1.633 m/s
The sum of vertical forces is given by mg where g is acceleration due to gravity and it's value taken as [tex]9.81 m/s^{2}[/tex]
Therefore, [tex]F_y=0.75\times 9.81=7.3575 N\approx 7.36 N[/tex]
The sum of forces in normal direction is given by [tex]Ma_n=Ks[/tex] therefore
[tex]Ma_n=200*0.1=20 N[/tex]
Therefore, normal force on the rod is 20 N
