chucky4433
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A bag has 2 green marbles, 3 red marbles, and 3 yellow marbles. What is the probabilty that you pick a yellow marble, do not replace it, and pick another yellow marble?
3/28
1/28
9/56
1/8

Respuesta :

TaeKwonDoIsDead

Answer:

[tex]\frac{3}{28}[/tex]

Step-by-step explanation:

We will find probability of picking yellow in first try (denote as P(y1) )

and then find probability of picking yellow in 2nd try ( denote as P(y2) )

and then multiply both to get our answer.

Total number of marbles = 2 + 3 + 3 = 8 marbles

Of them, 3 are yellow, so

P(y1) = 3/8

Now, since WITHOUT replacement, we have taken a yellow, that means there are now 2 yellow and total will decrease by 1 as well, so total is 7, So

P(y2) = 2/7

Now,

P(y1 and y2) = 3/8 * 2/7 = 6/56 = 3/28

The first one is the correct answer, [tex]\frac{3}{28}[/tex]

absor201

The probability that you pick a yellow marble, do not replace it, and pick another yellow marble is 3/28

Step-by-step explanation:

Given

Green marbles = 2

Red marbles =3

Yellow marbles = 3

Total marbles = n(S) = 8

The probability of drawing out a yellow marble will be: 3/8

When a marble is drawn out the remaining total marbles will be 7 and remaining yellow marbles will be 2:

The probability that you pick a yellow marble, do not replace it, and pick another yellow marble will be:

[tex]\frac{3}{8}*\frac{2}{7}\\=\frac{3*2}{8*7}\\=\frac{6}{56}\\=\frac{3}{28}[/tex]

The probability that you pick a yellow marble, do not replace it, and pick another yellow marble is 3/28

Keywords: Probability, Events

Learn more about probability at:

  • brainly.com/question/10435836
  • brainly.com/question/10541435

#LearnwithBrainly

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