For this case we have that by definition, the equation of the line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cut-off point with the y axis
We have the following equation:
[tex]y-4 = \frac {5} {2} (x-2)[/tex]
Algebraically manipulating we have:
[tex]y-4 = \frac {5} {2} x- \frac {5 * 2} {2}\\y-4 = \frac {5} {2} x- \frac {10} {2}\\y-4 = \frac {5} {2} x-5\\y = \frac {5} {2} x-5 + 4\\y = \frac {5} {2} x-1[/tex]
Thus, the slope of the line is [tex]\frac {5} {2}[/tex]
Answer:
The slope of the line is [tex]\frac {5} {2}[/tex]
