Answer:
[tex]g'=9.3345\ m.s^{-2}[/tex]
Explanation:
The minimum height of a space shuttle from the surface of the earth is 304 kilometers.
So according to this data we calculate the value to g at that height.
We have the formula:
[tex]g'=g(1-\frac{2h}{R} )[/tex]
where:
g' = the acceleration due to gravity at the given height 'h' above the earth
R = radius of the earth
g = the acceleration due to gravity at the surface of the earth
Now, using eq. (1)
[tex]g'=9.8(1-\frac{304\times 10^3}{64000\times 10^3} )[/tex]
[tex]g'=9.3345\ m.s^{-2}[/tex]
