Answer:
8.436 Nm
16.872 Nm
0
Explanation:
When we multiply the force with the distance at which the force is being applied we get torque
[tex]\tau=Frsin\theta[/tex]
where
F = Force = 111 N
r = Distance = 0.152 m
[tex]\theta[/tex] = Angle at which force is applied
When, [tex]\theta=30^{\circ}[/tex]
[tex]\tau=111\times 0.152sin30\\\Rightarrow \tau=8.436\ Nm[/tex]
The torque is 8.436 Nm
When, [tex]\theta=90^{\circ}[/tex]
[tex]\tau=111\times 0.152sin90\\\Rightarrow \tau=16.872\ Nm[/tex]
The torque is 16.872 Nm
When, [tex]\theta=180^{\circ}[/tex]
[tex]\tau=111\times 0.152sin180\\\Rightarrow \tau=0\ Nm[/tex]
The torque is 0
