Answer:
Sory if it is wrong.
Step-by-step explanation:
ln(x) is only defined for
x>−2
for real numbers.
xaxis intercepts occur when
y=0:y=ln
x+2)
ln(x+2)=0
This has no solution, because
excan never equal 0.
No x axis intercepts.
Y axis intercept occurs when
x=0
ln (0+2)=ln(2)≈
0.69314718
Vertical asymptotes occur where
ln
(x+2)
is undefined:ln
(x+2)
is undefined when
x=−2
So the line
x=−2
is a vertical asymptote. graph{ln(x+2) [-22.81, 22.8, -11.4, 11.41]}
