Answer:
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
Explanation:
[tex]C_6H_{12}O_6\rightarrow 2C_2H_5OH + 2CO_2[/tex]
Moles of glucose = [tex]\frac{510.6 g}{180 g/mol}=2.833 mol[/tex]
According to the reaction, 1 mol of gluocse gives 2 moles of ethanol.
Then 2.833 moles of glucose will give :
[tex]\frac{2}{1}\times 2.8333 mol=5.667 mol[/tex]
Mass of 5.667 moles of an ethanol :
5.667 mol × 46 g/mol = 260.682 g
Volume of ethanol = V
Density of the ethanol = 0.789 g/mL
[tex]Density=\frac{Mass}{Volume}[/tex]
[tex]0.789 g/mL=\frac{260.682 g}{V}[/tex]
[tex]V=\frac{260.682 g}{0.789 g/mL}=330.40 mL = 0.3304 L[/tex]
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
