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A friend on skis stands still on level ground, with dry 0.00°C with a coefficient of static friction of 0.0300. How hard would you have to push your friend in the forward horizontal direction to move him if your friend weighs 685 N?​

Respuesta :

MathPhys

Answer:

20.6 N

Explanation:

Friction equals normal force times coefficient of friction.

F = Fn μ

On level ground, normal force equal weight.

Fn = W

Therefore:

F = W μ

F = (685 N) (0.0300)

F = 20.6 N

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