Answer:
The uniform amount that can be used for scholaship, every year, first being at the end of the first year is $1,745.14
Explanation:
Hi, in order to find the amount that can be used to pay for school so the balance would last forever, given that $30,000 were left in the savings account, we need to solve for A the following equation.
[tex]PresentValue=\frac{A((1+r_{1} )^{n}-1) }{r_{1}(1+r_{1})^{n} } +\frac{A}{(r_{2})} \frac{1}{(1+r_{1})^n}[/tex]
Where;
r1 = 7%
r2 = 5%
n = 10
PresentValue = $30,000
Everything should look like this:
[tex]30,000=\frac{A((1+0.07)^{10}-1) }{0.07(1+0.07)^{10} } +\frac{A}{(0.05)} \frac{1}{(1+0.07)^10}[/tex]
[tex]30,000=A(7.023581541)+A(10.16698584)[/tex]
[tex]30,000=A(17.19056738)[/tex]
[tex]A=1,745.14[/tex]
So, uniform amount that could be used for the student scholarship each year, beginning at the end of the first year and continuing forever is $1,745.14
Best of luck.