Answer:
The wavelength at which maximum absorbance will be seen is 496.6 nm.
Explanation:
The energy difference between the HOMO and LUMO =E = 2.50 eV
The wavelength at which maximum absorbance will be observed is related to energy of the difference of the HOMO and LUMO.
[tex]E=\frac{hc}{\lambda }[/tex]
E = energy of photon of related to wavelength
h = Planck's constant = [tex]6.63\times 10^{-34}Js[/tex]
c = speed of light = [tex]3\times 10^8m/s[/tex]
[tex]\lambda[/tex] = wavelength = ?
E = 2.50 eV = [tex] =2.50\times 1.60218\times 10^{-19} J=4.0054 \times 10^{-19} J[/tex]
[tex]\lambda =\frac{6.63\times 10^{-34}Js\times 3\times 10^8 m/s}{4.0054 \times 10^{-19} J}=4.966\times 10^{-7} m[/tex]
[tex]\lambda =496.6 nm (1 m = 10^9 nm)[/tex]
The wavelength at which maximum absorbance will be seen is 496.6 nm.
The wavelength of maximum absorption is 495 nm.
Given that the energy is 2.50 eV, we have to convert the energy from ev to Joules.
1 ev = 1.6 × 10^-19 J
2.50 eV = 2.50 eV × 1.6 × 10^-19 J/1 ev
= 4 × 10^-19 J
Then;
E = hc/λ
c = speed of light = 3 × 10^8 m/s
h = Plank's constant = 6.6 × 10^-34 Js
λ = ?
E = 4 × 10^-19 J
λ = hc/E
λ = 6.6 × 10^-34 Js × 3 × 10^8 m/s/4 × 10^-19 J
λ = 4.95 × 10^-7
λ = 495 nm
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