Answer: It will reject the null hypothesis.
Step-by-step explanation:
Since we have given that
Hypothesis:
[tex]H_0:\mu=288.5\\\\H_a:\mu\neq 288.5[/tex]
n = 24
Average mean = 289.7 grams
Standard deviation = 5.6 grams
We need to find the 95% confidence interval.
Since n = 24 <30 , so we will use t test.
[tex]t=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\t=\dfrac{289.7-288.5}{\dfrac{5.6}{\sqrt{24}}}\\\\t=1.05[/tex]
Now, degrees of freedom = n- 1 = 24-1 =23
[tex]\alpha =1-0.95=0.05[/tex]
So, [tex]t_{\alpha ,df}=t_{0.05,23}=0.685[/tex]
Since t(calculated)>t
1.05>0.685
So, it will reject the null hypothesis.