Respuesta :
Answer:
The loaned amount at 11 % is $ 19,000
The loaned amount at 10 % is $ 2,500
Step-by-step explanation:
Given as :
The total loan amount = $21,500
The total interest earn = $2,340.00
The rate of interest are 11 % and 10 %
Let The loan amount at 11 % rate = $P
and The loan amount at 10 % rate = $21,500 - $P
Let The loan took for 1 year
Now, From Simple Interest method
Simple Interest = [tex]\dfrac{\textrm Principal\times \textrm Rate\times \textrm Time}{100}[/tex]
[tex]SI_1[/tex] = [tex]\dfrac{P_1\times R_1\times \textrm Time}{100}[/tex]
Or, [tex]SI_1[/tex] = [tex]\dfrac{P\times 11\times \textrm 1}{100}[/tex]
Similarly
[tex]SI_2[/tex] = [tex]\dfrac{21,500 - P\times 10\times \textrm 1}{100}[/tex]
∵ [tex]SI_1[/tex] + [tex]SI_2[/tex] = $2,340
Or, [tex]\dfrac{P\times 11\times \textrm 1}{100}[/tex] + [tex]\dfrac{21,500 - P\times 10\times \textrm 1}{100}[/tex] = $2,340
Or, 11 P - 10 P + 215000 = 234000
Or, P = 234000 - 215000
∴ P = $ 19,000
And $21,500 - $ 19,000 = $ 2,500
Hence The loaned amount at 11 % is $ 19,000
And The loaned amount at 10 % is $ 2,500 Answer
