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The distribution circuit of a residential power line is operated at 2000 V rms. This voltage must be reduced to 240 V rms for use within the residences. If the secondary side of the transformer has 475 turns, how many turns are in the primary?

Respuesta :

carlos2112

Answer:

[tex]N_p\approx3958[/tex]

Explanation:

In an ideal transformer the relationship between the voltages is proportional to the ratio between the number of turns of the windings. Thus:

[tex]\frac{V_p}{V_s} =\frac{N_p}{N_s}[/tex]

Where:

[tex]V_p=Voltage\hspace{3}in\hspace{3}primary\hspace{3}coil[/tex]

[tex]V_s=Voltage\hspace{3}in\hspace{3}secondary\hspace{3}coil[/tex]

[tex]N_p=Turns\hspace{3}on\hspace{3}primary\hspace{3}coil[/tex]

[tex]N_s=Turns\hspace{3}on\hspace{3}secondary\hspace{3}coil[/tex]

So, solving for [tex]N_p[/tex]

[tex]N_p=N_s*\frac{V_p}{V_s} =475*\frac{2000}{240} =3958.333333\approx3958[/tex]

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