Answer:
Explanation:
Given
mass of box [tex]m=5 kg[/tex]
coefficient of kinetic Friction [tex]\mu _k=0.5[/tex]
Box is moving with constant velocity therefore net Force on object is zero
Force applied=Frictional Force
Force applied[tex]=\mu mg[/tex]
[tex]Force=0.5\times 5\times 9.8=24.5 N[/tex]
(a)work done by applied Force
[tex]W=F\cdot s[/tex]
[tex]W=Fs\cos 0=24.5\times 0.1=2.45 J[/tex]
(b)Work done by Friction force
[tex]W=f\cdot s[/tex]
[tex]W=fs\cos (180)[/tex]
[tex]W=-fs=-24.5\times 0.1=-2.45 J[/tex]
(c)Total Work done =work done by Force+Work done by Frictional Force
[tex]W_{net}=2.45-2.45=0 J[/tex]
