Answer:
Step-by-step explanation:
Birth weights of full term babies are normally distributed with mean 7.13 pounds and standard deviation 1.29 pounds. Using normal distribution,
z = (x - μ) /σ
Where μ = mean
σ = standard deviation.
x = Birth weights of full term babies
From the information given,
μ = 7.13
σ = 1.29
x = 5.5
the probability that a randomly selected newborn is low-weight means that the newborn is weighing 5.5 pounds or less.
For P(x lesser than or equal to 55) ,
Z= (5.5-7.13)/1.29 = -1.63 /1.29 = -1.263
From the normal distribution table, the value of z = -1.263 = 0.1038
P(x lesser than or equal to 55) = 0.104
Based on the mean, standard deviation, and the weight of the new born, the probability that a randomly selected newborn is low-weight is 0.1038.
The probability that a baby is low weight can be found by first finding the z-score:
= P ( X < 5.5)
= (Weight limit - Mean) / Standard deviation
= (5.5 - 7.13) / 1.29
= -1.26
Then find the probability using the z table:
= P ( Z < - 1.26)
= 0.1038
Find out more on the z score at https://brainly.com/question/25638875.
