Answer:
KE= 30 J
Explanation:
Given that
m= 2.5 kg
r= 0.12 m
θ = 15°
h= 1.2 m
As we know that solid sphere rolls without slipping.It means that
v= ω r
v=Linear velocity
ω=Angular speed
r=radius
The total kinetic energy KE
[tex]KE=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2[/tex]
Moment of inertia of solid sphere I
[tex]I=\dfrac{2}{5}mr^2[/tex]
Now from energy conservation
Energy at top = Energy at bottom
The potential energy at top = m g h
Potential energy at bottom = 0
Kinetic energy at top = 0
Kinetic energy at bottom = KE
m g h + 0 = 0 + KE
KE= 2.5 x 10 x 1.2         ( take g =10 m/s²)
KE= 30 J
