The required equation is:
[tex]y=-3x-8[/tex]
Step-by-step explanation:
We need to find an equation of the line that passes through the point (-5,7) and is parallel to [tex]y=4-3x[/tex]
Finding Slope of required line:
The given equation is: [tex]y=4-3x[/tex]
Rearranging in slope intercept form: [tex]y=-3x+4[/tex]
Comparing to standard slope intercept form [tex]y=mx+b[/tex] where m is slope, the slope is -3.
Since the lines are parallel and parallel lines have same slope of slope m= -3
Finding y-intercept (b):
We have slope = -3 and point(-5,7) where x = -5 and y =7
Putting values in the formula of slope intercept form:
[tex]y=mx+b\\7=-3(-5)+b\\7=15+b\\b=7-15\\b=-8[/tex]
So, value of b = -8.
Putting value of slope and y-intercept to find the required equation:
[tex]y=mx+b\\y=-3x-8[/tex]
So, The required equation is:
[tex]y=-3x-8[/tex]
Keywords: Equation of lines
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Answer: y=-3x-8
Step-by-step explanation:
y=mx+b
7=-3(-5)+b
7=15+b
b=7-15
b=-8
So, value of b = -8.
Putting value of slope and y-intercept to find the required equation:
y=mx+b
y=-3x-8
Hope this helps, have a BLESSED day! :-)
-Cutiepatutie
