Answer:[tex]2.71\times 10^4 km[/tex]
Explanation:
Given
Speed of satellite [tex]v_1=4.42 km/s[/tex] At Perigee
Speed at apogee [tex]v_2=3.64 km/s[/tex]
Distance from center to Perigee [tex]r_1=2.24\times 10^{4} Km[/tex]
Let [tex]r_2[/tex] be the distance of Apogee
According to Kepler's Second law angular Momentum is conserved
[tex]mv_1r_1=mv_1r_2[/tex]
[tex]v_1r_1=v_2r_2[/tex]
[tex]4.42\times 2.24\times 10^4=3.64\times r_2[/tex]
[tex]r_2=\frac{4.42}{3.64}\times 2.24\times 10^4[/tex]
[tex]r_2=2.71\times 10^4 Km[/tex]
