An object slides on a level floor. It slows and comes to a stop with a constant acceleration of magnitude 2.4 m/s2. What is the coefficient of kinetic friction between the object and the floor?

Respuesta :

Answer:

0.245

Explanation:

Force of the object = mass *acceleration of the body = 2.4m where m = mass,

And the Frictional force = force acting on the object due to its acceleration.

The force of normal due to the weight of the body = m*9.81.

Coefficient of kinetic friction = 2.4m/ 9.81m = 0.245.

The coefficient of kinetic friction is 0.245

Coefficient of friction:

The frictional force F acting on an object is given by the product of the coefficient of friction μ and the normal reaction N force acting on the body.

Now, the normal force is the equal and opposite reaction of the weight or the force due to gravity on the body of mass m.

N = mg

So frictional force, F = μmg.

Also from Newton's laws of motion, the force acting on a body is given by:

F = ma, where a is the acceleration = 2.4 m/s².

ma = μmg

μ = a/g

μ = 2.4/9.8

μ = 0.245

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